C 语言的三子棋，用 22 天总结了一份完美的 SQL 学习笔记
}
else
{
printf("该输入的坐标已经被占用\n");
}
}
else
{
printf("输入坐标错误\n");
}
}
}
[](()电脑下棋
电脑设置两个随机值，再将进行条件判断
void ComputerMove(char board[ROW][COL], int row, int col)
{
printf("电脑走>\n");
while (1)
{
int x = rand() % row;
int y = rand() % col;
if (board[x][y] == ' ')
{
board[x ][y ] = '#';
break;
}
}
}
[](()三子棋的判断胜负
是否有 3 个"@“能否连接成一条直线如果有则玩家获胜，是否有 3 个”#"能否连接成一条直线如果有则玩家获胜，如果棋盘已满没有获得胜利则为平均。
int IsFull(char board[ROW][COL], int row, int col)
{
int i = 0;
int j = 0;
for (i = 0; i < row; i++)
{
for (j = 0; j < col; j++)
{
if (board[i][j] == ' ')
{
return 0;
}
}
}
return 1;
}
char IsWin(char board[ROW][COL], int row, int col)
{
int i = 0;
for (i = 0; i < row; i++)
{
if (board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][0] != ' ')
{
return board[i][0];
}
}
for (i = 0; i < col; i++)
{
if (board[0][i] == board[1][i] && board[1][i] == board[2][i] && board[0][i] != ' ')
{
return board[0][i];
}
}
if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[1][1] != ' ')
return board[1][1];
if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[1][1] != ' ')
return board[1][1];
if (IsFull(board, row, col))
{
return 'Q';
}
return 'C';
}
[](()总代码
#pragma once
#include<time.h>
#include<stdlib.h>
#include<stdio.h>
#define ROW 3
#define COL 3
//初始化棋盘
void InitBoard(char board[ROW][COL], int row, int col);
//打印棋盘
void DisplayBoard(char board[ROW][COL], int row, int col);
//玩 《一线大厂 Java 面试题解析+后端开发学习笔记+最新架构讲解视频+实战项目源码讲义》开源 家下棋
void PlayerMove(char board[ROW][COL], int row, int col);
//电脑下棋
void ComputerMove(char board[ROW][COL], int row, int col);
//判断游戏的输赢
char IsWin(char board[ROW] Java 开源项目【ali1024.coding.net/public/P7/Java/git】 [COL], int row, int col);
void InitBoard(char board[ROW][COL], int row, int col)
{
for (int i = 0; i < row; i++)
{
int j = 0;
for (j = 0; j < col; j++)
{
board[i][j] = ' ';
}
}
}
void DisplayBoard(char board[ROW][COL], int row, int col)
{
int i = 0;
for (i = 0; i < row; i++)
{
int j = 0;
for (j = 0; j < col; j++)
{
printf(" %c ", board[i][j]);
if (j < col - 1)
printf("|");
}
printf("\n");
if (i < row - 1)
{
for (j = 0; j < col; j++)
{
printf("---");
if (j < col - 1)
printf("|");
}
}
printf("\n");
}
}
void PlayerMove(char board[ROW][COL], int row, int col)
{
int x = 0;
int y = 0;
while (1)
{
printf("请选择第三子棋坐标>");
scanf("%d%d",&x,&y);
if ((x >= 1 && x <= row) && (y >= 1 && y <= col))
{
if (board[x - 1][y - 1] == ' ')
{
board[x - 1][y - 1] = '@';
break;
}
else
{
printf("该输入的坐标已经被占用\n");
}
}
else
{
printf("输入坐标错误\n");
}
}
}
void ComputerMove(char board[ROW][COL], int row, int col)
{
printf("电脑走>\n");
while (1)
{
int x = rand() % row;
int y = rand() % col;
if (board[x][y] == ' ')
{
board[x ][y ] = '#';
break;
}
}
}
int IsFull(char board[ROW][COL], int row, int col)
{
int i = 0;
int j = 0;
for (i = 0; i < row; i++)
{
for (j = 0; j < col; j++)
{
if (board[i][j] == ' ')
{
return 0;
}
}
}
return 1;
}
char IsWin(char board[ROW][COL], int row, int col)
{
int i = 0;
for (i = 0; i < row; i++)
{
if (board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][0] != ' ')
{
return board[i][0];
}
}
for (i = 0; i < col; i++)
{
if (board[0][i] == board[1][i] && board[1][i] == board[2][i] && board[0][i] != ' ')
{
return board[0][i];
}
}
if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[1][1] != ' ')
return board[1][1];
if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[1][1] != ' ')
return board[1][1];
最后总结
搞定算法，面试字节再不怕，有需要文章中分享的这些二叉树、链表、字符串、栈和队列等等各大面试高频知识点及解析
最后再分享一份终极手撕架构的大礼包(学习笔记)：分布式+微服务+开源框架+性能优化
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