写点什么

并发王者课 - 青铜 6:借花献佛 - 如何格式化 Java 内存工具 JOL 输出

用户头像
秦二爷
关注
发布于: 2021 年 05 月 27 日

在前面的文章《一探究竟-如何从 synchronized 理解 Java 对象头中的锁》中,我们介绍并体验了 JOL 工具。虽然 JOL 很赞,但它的输出对我们不是很友好,如果不借助工具,我们很难直观理解其中的含义。


下面这段代码是对 JOL 输出的翻译,建议你收藏。代码非我所写,文末已经注明出处



import org.openjdk.jol.info.ClassLayout;
import java.nio.ByteOrder;import java.util.ArrayList;import java.util.Collections;import java.util.List;import java.util.regex.Matcher;import java.util.regex.Pattern;
public class PrintObjectHeader { /** * Get binary data * * @param o * @return */ public static String getObjectHeader(Object o) { ByteOrder order = ByteOrder.nativeOrder();//Byte order String table = ClassLayout.parseInstance(o).toPrintable(); Pattern p = Pattern.compile("(0|1){8}"); Matcher matcher = p.matcher(table); List<String> header = new ArrayList<String>(); while (matcher.find()) { header.add(matcher.group()); } //Little-endian machines, need to traverse in reverse StringBuilder sb = new StringBuilder(); if (order.equals(ByteOrder.LITTLE_ENDIAN)) { Collections.reverse(header); } for (String s : header) { sb.append(s).append(" "); } return sb.toString().trim(); }
/** * Parsing object header function for 64bit jvm * In 64bit jvm, the object header has two parts: Mark Word and Class Pointer, Mark Word takes 8 bytes, Class Pointer takes 4 bytes * * @param s Binary string of object header (each 8 bits, separated by a space) */ public static void parseObjectHeader(String s) { String[] tmp = s.split(" "); System.out.print("Class Pointer: "); for (int i = 0; i < 4; ++i) { System.out.print(tmp[i] + " "); } System.out.println("\nMark Word:"); if (tmp[11].charAt(5) == '0' && tmp[11].substring(6).equals("01")) {//0 01 lock-free state, regardless of GC mark //notice: Mark word structure without lock: unused(25bit) + hashcode(31bit) + unused(1bit) + age(4bit) + biased_lock_flag(1bit) + lock_type(2bit) // The reason why hashcode only needs 31bit is: hashcode can only be greater than or equal to 0, eliminating the negative range, so you can use 31bit to store System.out.print("\thashcode (31bit): "); System.out.print(tmp[7].substring(1) + " "); for (int i = 8; i < 11; ++i) System.out.print(tmp[i] + " "); System.out.println(); } else if (tmp[11].charAt(5) == '1' && tmp[11].substring(6).equals("01")) {//1 01, which is the case of biased lock //notice: The object is in a biased lock, its structure is: ThreadID(54bit) + epoch(2bit) + unused(1bit) + age(4bit) + biased_lock_flag(1bit) + lock_type(2bit) // ThreadID here is the thread ID holding the biased lock, epoch: a timestamp of the biased lock, used for optimization of the biased lock System.out.print("\tThreadID(54bit): "); for (int i = 4; i < 10; ++i) System.out.print(tmp[i] + " "); System.out.println(tmp[10].substring(0, 6)); System.out.println("\tepoch: " + tmp[10].substring(6)); } else {//In the case of lightweight locks or heavyweight locks, regardless of the GC mark //notice: JavaThread*(62bit,include zero padding) + lock_type(2bit) // At this point, JavaThread* points to the monitor of the lock record/heavyweight lock in the stack System.out.print("\tjavaThread*(62bit,include zero padding): "); for (int i = 4; i < 11; ++i) System.out.print(tmp[i] + " "); System.out.println(tmp[11].substring(0, 6)); System.out.println("\tLockFlag (2bit): " + tmp[11].substring(6)); System.out.println(); return; } System.out.println("\tage (4bit): " + tmp[11].substring(1, 5)); System.out.println("\tbiasedLockFlag (1bit): " + tmp[11].charAt(5)); System.out.println("\tLockFlag (2bit): " + tmp[11].substring(6));
System.out.println(); }
public static void printObjectHeader(Object o) { if (o == null) { System.out.println("null object."); return; } parseObjectHeader(getObjectHeader(o)); }}
复制代码


参考资料


  • https://www.programmersought.com/article/21094532407/

关于作者

关注公众号【庸人技术笑谈】,获取及时文章更新。记录平凡人的技术故事,分享有品质(尽量)的技术文章,偶尔也聊聊生活和理想。不贩卖焦虑,不兜售课程。


如果本文对你有帮助,欢迎点赞关注

发布于: 2021 年 05 月 27 日阅读数: 69
用户头像

秦二爷

关注

微信公众号:【庸人技术笑谈】 2018.05.13 加入

记录平凡人的技术故事,分享有品质(尽量)的技术文章,偶尔也聊聊生活和理想。不贩卖焦虑,不兜售课程。

评论

发布
暂无评论
并发王者课-青铜6:借花献佛-如何格式化Java内存工具JOL输出