在 SQL SERVER 中实现 RSA 加解密函数，java 入门书籍推荐
if object_id('p_createKey') is not null
drop proc p_createKey
go
create proc p_createKey
@p int,@q int
as
begin
declare @n bigint,@t bigint,@flag int,@d int
if dbo.f_primeNumTest(@p)=0
begin
print cast(@p as varchar)+'不是素数，请重新选择数据'
return
end
if dbo.f_primeNumTest(@q)=0
begin
print cast(@q as varchar)+'不是素数，请重新选择数据'
return
end
print '请从下列数据中选择其中一对，作为密钥'
select @n=@p*@q,@t=(@p-1)*(@q-1)
declare @e int
set @e=2
while @e<@t
begin
if dbo.f_isNumsPrime(@e,@t)=0
begin
set @d=2
while @d<@n
begin
if(@e*@d%@t=1)
print cast(@e as varchar)+space(5)+cast(@d as varchar)
set @d=@d+1
end
end
set @e=@e+1
end
end
--加密函数
[@key](
)?为上一个存储过程中选择的密码中的一个,[@p](
) ,[@q](
)?产生密钥对时选择的两个数。获取每一个字符的 unicode 值，然后进行加密，产生个字节的位数据
if object_id('f_RSAEncry') is not null
drop function f_RSAEncry
go
create function f_RSAEncry
(@s varchar(100),@key int ,@p int ,@q int)
returns nvarchar(4000)
as
begin
declare @crypt varchar(8000)
set @crypt=''
while len(@s)>0
begin
declare @i bigint,@tmp varchar(10),@k2 int,@leftchar int
select @leftchar=unicode(left(@s,1)),@k2=@key/2,@i=1
while @k2>0
begin
set @i=(cast(power(@leftchar,2) as bigint)@i)%(@p@q)
set @k2=@k2-1
end
set @i=(@leftchar*@i)%(@p*@q)
set @tmp=''
select @tmp=case when @i%16 between 10 and 15 then char( @i%16+55) else cast(@i%16 as varchar) end+@tmp,@i=@i/16
from (select number from master.dbo.spt_values where type='p' and number<10 )K
order by number desc
set @crypt=@crypt+right(@tmp,6)
set @s=stuff(@s,1,1,'')
end
return @crypt
end
--解密
[@key](
)?为一个存储过程中选择的密码对中另一个数字,[@p](
) ,@q?产生密钥对时选择的两个数
if object_id('f_RSADecry') is not null
drop function f_RSADecry
go
create function f_RSADecry
(@s nvarchar(4000),@key int ,@p int ,@q int)
returns nvarchar(4000)
as
begin
declare @crypt varchar(8000)
set @crypt=''
while len(@s)>0
begin
declare @leftchar bigint
select @leftchar=sum(data1)
from (select case upper(substring(left(@s,6), number, 1)) when 'A' then 10
when 'B' then 11
when 'C' then 12
when 'D' then 13
when 'E' then 14
when 'F' then 15
else substring(left(@s,6), number, 1)
end* power(16, len(left(@s,6)) - number) data1
from (select number from master.dbo.spt_values where type='p')K
where number <= len(left(@s,6))
) L
declare @k2 int,@j bigint
select @k2=@key/2,@j=1
while @k2>0
begin
set @j=(cast(power(@leftchar,2)as bigint)@j)%(@p@q)
set @k2=@k2-1
end
set @j=(@leftchar*@j)%(@p*@q)
set @crypt=@crypt+nchar(@j)
set @s=stuff(@s,1,6,'')
end
return @crypt
end
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