代码随想录 Day39 - 动态规划(二)
作者:jjn0703
- 2023-08-06 江苏
本文字数:1502 字
阅读完需:约 5 分钟
作业题
62. 不同路径
初始化:dp[0][0~width] = 1, dp[0~height][0] = 1.
递推公式: dp[i][j] = dp[i - 1][j] + dp[i][j - 1] ( i>= 1, j >= 1)
package jjn.carl.dp;
import java.util.Scanner;
/**
* @author Jjn
* @since 2023/8/6 14:58
*/
public class LeetCode62 {
public int uniquePaths(int m, int n) {
int[][] dp = new int[m][n];
for (int i = 0; i < n; i++) {
dp[0][i] = 1;
}
for (int i = 0; i < m; i++) {
dp[i][0] = 1;
}
for (int i = 1; i < m; i++) {
for (int j = 1; j < n; j++) {
dp[i][j] = dp[i - 1][j] + dp[i][j - 1];
}
}
return dp[m - 1][n - 1];
}
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int m = scanner.nextInt();
int n = scanner.nextInt();
int uniquePaths = new LeetCode62().uniquePaths(m, n);
System.out.println(uniquePaths);
}
}
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63. 不同路径 II
初始化:dp[0][0~width] = 1, dp[0~height][0] = 1.
递推公式:
如果
obstacleGrid[i][j] == 0:
dp[i][j] = dp[i - 1][j] + dp[i][j - 1] ( i>= 1, j >= 1)
obstacleGrid[i][j] == 1:
dp[i][j] = 0
package jjn.carl.dp;
import jjn.round1.LeetCode171_ExcelSheetColumnNumber;
import java.util.Scanner;
/**
* @author Jjn
* @since 2023/8/6 15:04
*/
public class LeetCode63 {
public int uniquePathsWithObstacles(int[][] obstacleGrid) {
int height = obstacleGrid.length, width = obstacleGrid[0].length;
int[][] dp = new int[height][width];
for (int i = 0; i < height; i++) {
if (obstacleGrid[i][0] == 1) {
for (int j = i; j < height; j++) {
dp[j][0] = 0;
i = j;
}
} else {
dp[i][0] = 1;
}
}
for (int i = 0; i < width; i++) {
if (obstacleGrid[0][i] == 1) {
for (int j = i; j < width; j++) {
dp[0][j] = 0;
i = j;
}
} else {
dp[0][i] = 1;
}
}
for (int i = 1; i < height; i++) {
for (int j = 1; j < width; j++) {
if (obstacleGrid[i][j] == 1) {
dp[i][j] = 0;
} else {
dp[i][j] = dp[i - 1][j] + dp[i][j - 1];
}
}
}
return dp[height - 1][width - 1];
}
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int height = scanner.nextInt();
int width = scanner.nextInt();
int[][] obstacleGrid = new int[height][width];
for (int i = 0; i < height; i++) {
for (int j = 0; j < width; j++) {
obstacleGrid[i][j] = scanner.nextInt();
}
}
int uniquePathsWithObstacles = new LeetCode63().uniquePathsWithObstacles(obstacleGrid);
System.out.println(uniquePathsWithObstacles);
}
}
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版权声明: 本文为 InfoQ 作者【jjn0703】的原创文章。
原文链接:【http://xie.infoq.cn/article/143108531a51e927cde051ffe】。文章转载请联系作者。
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