C# 之 扑克游戏 -- 21 点规则介绍和代码实现
- 2023-04-25 辽宁
本文字数:5428 字
阅读完需:约 18 分钟
一,游戏介绍
1.1 游戏规则
21 点又名黑杰克,该游戏由 2 到 6 个人玩,使用除大小王之外的 52 张牌,游戏者的目标是使手中的牌的点数之和不超过 21 点且尽量大。
1.2 牌点计算
A 至 10 牌,按其原点数计算;J、Q、K 都算作 10 点。
1.3 判断胜负
二十一点玩法规则和概率在二十一点游戏中,拥有最高点数的玩家获胜,其点数必须等于或低于 21 点;超过 21 点的玩家称为爆牌。拥有最高点数的玩家获胜,其点数必须等于或低于 21 点;超过 21 点之间判负。
二,游戏设计
2.1 游戏流程
发牌:玩家和 AI 每人发两张牌,由手牌点数和大的玩家优先选择是否在牌堆中取牌
取牌:手牌点数和小于 21,等待 1 中优先选择后再顺时针轮到其他玩家选择是否取牌
取牌后:若牌点大于 21 则直接判负出局,场上只剩 1 人,直接游戏结束;否则重复 2-3 若牌点小于等于 21 则轮到下家取牌,重复 2-3
游戏结束其他玩家取牌后都超过 21 点,只剩 1 人,直接获胜所有玩家都选择不取牌后,按规则比较所有玩家手牌点数和,牌点大的获胜。
2.2 玩家类
由玩家自己选择是否继续拿牌。(输入 Y 继续拿牌,N 为不拿牌)
2.3 AI 类
简化 AI 逻辑,发牌后 AI 手牌和为 4-8 时继续拿牌,一直到 17 点或 17 点以上不再拿牌;因为此时再拿牌就有一半以上的概率超过 21 点。
三,参考代码
using System;
namespace _21dian
{
using System;
using System.Collections.Generic;
namespace Game21Points
{
class Project
{
static void Main(string[] args)
{
Console.WriteLine("----- 游戏开始 -----");
// 扑克牌
List<int> cards = new List<int>()
{
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13,
14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26,
27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39,
40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52
};
// 创建对象
Poker poker = new Poker(cards);
Player player = new Player();
AIPlayer ai = new AIPlayer();
// --> 玩家入场
player.playerName = "Czhenya";
ai.playerName = "AI";
poker.AddPlayer(player);
poker.AddPlayer(ai);
// 事件关系绑定
poker.GameSratrHandler += player.GameStart;
poker.GameSratrHandler += ai.GameStart;
// 游戏开始
poker.GameStart();
// 每人发两张牌
poker.SendCard();
poker.SendCard();
// 询问取牌
poker.TaskCard();
Console.ReadKey();
}
}
abstract class AbsPlayer
{
public string playerName;
public bool IsContinueTakeCard = true;
public List<int> handCards = new List<int>();
public abstract void GameStart();
public virtual void SendCard(int card)
{
handCards.Add(card);
}
public abstract bool TakeCard();
public bool GameOver()
{
bool isGameOver;
if (HandCardsPoint > 21)
{
isGameOver = true;
}
else
{
isGameOver = !IsContinueTakeCard;
}
return isGameOver;
}
public int HandCardsPoint { get { return PokeTools.HandCardsSum(handCards); } }
}
class Player : AbsPlayer
{
public override void GameStart()
{
handCards.Clear();
Console.WriteLine("玩家整理了一下衣服,准备开局;");
}
public override void SendCard(int card)
{
handCards.Add(card);
Console.WriteLine("玩家发牌:" + PokeTools.PokerBrandByPoint(card));
}
public override bool TakeCard()
{
Console.WriteLine("当前您的手牌点数和为:" + HandCardsPoint);
Console.WriteLine("是否继续取牌(Y/N)?");
string readStr = Console.ReadLine();
// 输入Y取牌,其他为不取牌
IsContinueTakeCard = readStr.Equals("Y");
return IsContinueTakeCard;
}
}
class AIPlayer : AbsPlayer
{
public override void GameStart()
{
handCards.Clear();
Console.WriteLine("AI:清理一下内存,与之一战;");
}
public override void SendCard(int card)
{
base.SendCard(card);
Console.WriteLine("AI发牌:" + PokeTools.PokerBrandByPoint(card));
}
public override bool TakeCard()
{
// 手牌数点数小于17,就继续取牌
return HandCardsPoint < 17;
}
}
class Poker
{
List<AbsPlayer> players = new List<AbsPlayer>();
public Action GameSratrHandler;
public Action<int> SendCardHandler;
public Func<int, bool> TaskCardHandler;
// 发牌用
List<int> sendCards;
public Poker(List<int> cards)
{
// 复制一份发牌用
sendCards = new List<int>(cards);
}
public void AddPlayer(AbsPlayer player)
{
players.Add(player);
}
public void GameStart()
{
for (int i = 0; i < players.Count; i++)
{
if (!players[i].GameOver())
{
players[i].GameStart();
}
}
}
/// <summary>
/// 发牌 -- 会剔除已经发过的牌
/// </summary>
public void SendCard()
{
for (int i = 0; i < players.Count; i++)
{
players[i].SendCard(SendOneCard());
}
}
int SendOneCard()
{
// 随机发一张牌
Random random = new Random();
int index = random.Next(0, sendCards.Count);
// 取到牌值
int cardPoint = sendCards[index];
// 从手牌中移除 --> 为避免发到相同的牌
sendCards.RemoveAt(index);
return cardPoint;
}
public void TaskCard()
{
for (int i = 0; i < players.Count; i++)
{
// 选择取牌后再发一张牌
if (players[i].TakeCard())
{
players[i].SendCard(SendOneCard());
}
Console.WriteLine($"玩家:{players[i].playerName} 手牌:{PokeTools.ShowHandCard(players[i].handCards)}");
}
if (!GameOver())
{
TaskCard();
}
}
public bool GameOver()
{
int playerCount = 0;
for (int i = 0; i < players.Count; i++)
{
if (!players[i].GameOver())
{
playerCount++;
}
}
bool isGameOver = playerCount <= 1;
if (isGameOver)
{
Console.WriteLine("游戏结束:");
List<AbsPlayer> playerList = new List<AbsPlayer>();
int maxPoint = 0;
for (int i = 0; i < players.Count; i++)
{
if (players[i].HandCardsPoint > 21)
{
Console.WriteLine($"玩家:{players[i].playerName} 爆牌了" );
}
else
{
playerList.Add(players[i]);
if (maxPoint < players[i].HandCardsPoint)
{
maxPoint = players[i].HandCardsPoint;
}
}
}
if (playerList.Count == 0)
{
Console.WriteLine("平局");
}
else if (playerList.Count == 1)
{
Console.WriteLine($"玩家:{playerList[0].playerName} 赢了");
}
else
{
for (int i = 0; i < playerList.Count; i++)
{
if (maxPoint == playerList[i].HandCardsPoint)
{
Console.WriteLine($"玩家:{playerList[i].playerName} 赢了");
}
}
}
}
return isGameOver;
}
}
}
class PokeTools
{
/// <summary>
/// 根据牌点返回牌名 如:14 ->红桃3
/// </summary>
/// <param name="card"></param>
/// <returns></returns>
public static string PokerBrandByPoint(int card)
{
if (card > 52 || card <= 0)
{
Console.WriteLine("不是扑克牌点");
return "不是扑克牌点";
}
string[] flowerColor = new string[4] { "黑桃", "红桃", "梅花", "方片" };
string[] points = new string[13] { "K", "A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q" };
int huaSe = (card - 1) / 13;
int point = card % 13;
// 返回花色 + 牌点 如:红桃3
return flowerColor[huaSe] + points[point];
}
/// <summary>
/// 手牌求和
/// </summary>
/// <param name="handCards"></param>
/// <returns></returns>
public static int HandCardsSum(List<int> handCards)
{
// "K", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q"
int[] points = new int[13] { 10, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10 };
int sumRes = 0;
for (int i = 0; i < handCards.Count; i++)
{
sumRes += points[handCards[i] % 13];
}
return sumRes;
}
// 显示手牌
public static (string, string) ShowHandCard(List<int> handCards)
{
string resStr = "";
for (int i = 0; i < handCards.Count; i++)
{
resStr += PokeTools.PokerBrandByPoint(handCards[i]);
if (handCards.Count - 1 != i)
{
resStr += ",";
}
}
return (resStr, "牌点和:" + PokeTools.HandCardsSum(handCards));
}
}
}
测试结果:
版权声明: 本文为 InfoQ 作者【陈言必行】的原创文章。
原文链接:【http://xie.infoq.cn/article/f2cdd90094d23612c3e3536b2】。未经作者许可,禁止转载。
陈言必行
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