一维数组的动态和

package simple;
import org.junit.Test;
public class Solution_1480 {    /**     *  1480.一维数组的动态和     * 给你一个数组 nums 。数组「动态和」的计算公式为：runningSum[i] = sum(nums[0]…nums[i])     * @param nums     * @return     */    public int[] runningSum(int[] nums) {        int[] result = new int[nums.length];        result[0] = nums[0];        for (int i = 1; i < nums.length; i++) {            result[i] = result[i-1]+nums[i];        }        return result;    }
    /**     *  这种方式,覆盖了原数组内容, 执行效率和上一种方式一样, 但是更节省了内存     * @param nums     * @return     */    public int[] runningSum2(int[] nums) {        for (int i = 1; i < nums.length; i++) {            nums[i] = nums[i]+nums[i-1];        }        return nums;    }
    @Test    public void testMethod(){        Solution_1480 solution = new Solution_1480();        int[] sum = solution.runningSum(new int[]{1, 2, 3, 4});        for (int inti : sum) {            System.out.println(inti);        }    }}