架构师训练营第 08 周——练习

public ListNode getIntersectionNode(ListNode headA, ListNode headB) {
    if ((headA == null) || (headB == null)) {
        return null;
    }
    ListNode a = headA;
    ListNode b = headB;
    while (a != b) {
        a = (a == null) ? headB : a.next;
        b = (b == null) ? headA : b.next;
    }
    return a;
}