关于 web 自动化过程中滑块解锁问题以及页面滚动的问题的研究

根据滑块本身的大小以及承载滑块的div的大小来获取偏移量offx    slide1_back = self.find_ele_is_presence(_slide1_back_locate)    slide1_span = self.find_ele_is_presence(_slide1_span_locate)    获取滑块的起始坐标location    start_location = slide1_span.location    # 获取滑块所在长条的长宽大小    background_size = slide1_back.size    4.滑块的滑动范围[开始位置的横坐标减去滑片的宽度],由于是平移所以纵坐标没有变化    x_location = background_size["width"] - start_location["x"]    y_location = start_location["y"]

def ease_out_quad(x):    return 1 - (1 - x) * (1 - x)

def ease_out_quart(x):    return 1 - pow(1 - x, 4)

def ease_out_expo(x):    if x == 1:        return 1    else:        return 1 - pow(2, -10 * x)

def get_tracks(distance, seconds):    """    :param distance: offset    :param seconds: 拉动时间    :return:    """    tracks = [0]    offsets = [0]    # print("np_value:", np.arange(0.0, seconds, 0.1))    for t in np.arange(0.0, seconds, 0.1):        offset = round(ease_out_quart(t / seconds) * distance)        tracks.append(offset - offsets[-1])        offsets.append(offset)    return offsets, tracks

def test_scroll_to():    chromeOptions = webdriver.ChromeOptions()    chromeOptions.add_argument('--start-maximized')    driver = webdriver.Chrome(chromeOptions)
    driver.get('https://www.jd.com/')    n=1    while True:        # driver.execute_script(f"document.body.scrollTop = {100*n};")        driver.execute_script(f"window.scrollTo({(n-1)*50}, {n*50})")        n+=1

document.querySelector('.page-content').scrollTo(0,300)
document.querySelector('.ant-table-content').scrollTo(-100,0)通过定位到存在内嵌滚动条的元件，然后使用scrollTo(x,y)进行滚动。